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Popular >

y^'=y-16

Solution

y^{^{'}} = y - 16

Solution

y = e^{t + c_{1}} + 16

Solution steps

y^{'} (t) = y - 16

Solve separable ODE:

y = e^{t + c_{1}} + 16

y = e^{t + c_{1}} + 16

Graph

Popular Examples

y^'=y(5t^4-6t^5),y(0)=1

y^{^{'}} = y (5 t^{4} - 6 t^{5}), y (0) = 1

y^{^{'}} - k^{2} y = 0

y^'-2y^{1/3}=0,y(0)=0

y^{^{'}} - 2 y^{\frac{1}{3}} = 0, y (0) = 0

y^'-(7y)/(5160)=0.07

y^{^{'}} - \frac{7 y}{5160} = 0.07

(dy}{dx}=\frac{xcos(x))/y ,y(0)=-2

\frac{d y}{d x} = \frac{x cos ( x )}{y}, y (0) = - 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=y-16 ?
The solution for y^'=y-16 is y=e^{t+c_{1}}+16