What is the solution for 2y^{''}+11y^'-6y=0 ?

The solution for 2y^{''}+11y^'-6y=0 is y=c_{1}e^{t/2}+c_{2}e^{-6t}

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2y^{''}+11y^'-6y=0

2 y^{^{''}} + 11 y^{^{'}} - 6 y = 0

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 6 t}

Solution steps

2 y^{''} (t) + 11 y^{'} (t) - 6 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 6 t}

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- 6 t}

\frac{d y}{d x} = \frac{y}{x ^{3} + 3 x ^{2} + 2 x}

f (x) = ln (1 + sin (\frac{4}{x ^{2}}))

y = sin (4 x) + sin^{2} (4 x), (0, 0)

3 y d x + 2 x d y = 0

\int_{0}^{\infty} e^{- 4 x} d x

What is the solution for 2y^{''}+11y^'-6y=0 ?
The solution for 2y^{''}+11y^'-6y=0 is y=c_{1}e^{t/2}+c_{2}e^{-6t}