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Popular >

t^2y^{''}-8ty^'+8y=0

Solution

t^{2} y^{^{''}} - 8 t y^{^{'}} + 8 y = 0

Solution

y = c_{1} t^{8} + c_{2} t

Solution steps

t^{2} y^{''} (t) - 8 t y^{'} (t) + 8 y = 0

Solve linear ODE:

y = c_{1} t^{8} + c_{2} t

y = c_{1} t^{8} + c_{2} t

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y^{''}+4y^'+13y=0,y(0)=7,y^'(0)=7

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (0) = 7, y^{^{'}} (0) = 7

Frequently Asked Questions (FAQ)

What is the solution for t^2y^{''}-8ty^'+8y=0 ?
The solution for t^2y^{''}-8ty^'+8y=0 is y=c_{1}t^8+c_{2}t