What is the derivative of sin((2x)/(x+1)) ?

The derivative of sin((2x)/(x+1)) is (2cos(\frac{2x)/(x+1))}{(x+1)^2}

What is the first derivative of sin((2x)/(x+1)) ?

The first derivative of sin((2x)/(x+1)) is (2cos(\frac{2x)/(x+1))}{(x+1)^2}

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derivative of

sin (\frac{2 x}{x + 1})

\frac{2 cos ( \frac{2 x}{x + 1} )}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (sin (\frac{2 x}{x + 1}))

Apply the chain rule:

cos (\frac{2 x}{x + 1}) \frac{d}{d x} (\frac{2 x}{x + 1})

= cos (\frac{2 x}{x + 1}) \frac{d}{d x} (\frac{2 x}{x + 1})

\frac{d}{d x} (\frac{2 x}{x + 1}) = \frac{2}{( x + 1 ) ^{2}}

= cos (\frac{2 x}{x + 1}) \frac{2}{( x + 1 ) ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 cos ( \frac{2 x}{x + 1} )}{( x + 1 ) ^{2}}

\int 7 x^{2} y + \frac{3}{x} - 1 d x

\frac{\partial}{\partial x} (12 y^{2} x^{2} - 6 y x)

\frac{d}{d x} (sin^{4} (4 x))

\frac{d x}{d y} = 3 x (5 - x)

(3 t + 6 y + 3) = \frac{d y}{d t}

What is the derivative of sin((2x)/(x+1)) ?
The derivative of sin((2x)/(x+1)) is (2cos(\frac{2x)/(x+1))}{(x+1)^2}
What is the first derivative of sin((2x)/(x+1)) ?
The first derivative of sin((2x)/(x+1)) is (2cos(\frac{2x)/(x+1))}{(x+1)^2}