What is the derivative of 16e^{4x} ?

The derivative of 16e^{4x} is 64e^{4x}

What is the first derivative of 16e^{4x} ?

The first derivative of 16e^{4x} is 64e^{4x}

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\frac{d}{d x} (16 e^{4 x})

64 e^{4 x}

Solution steps

\frac{d}{d x} (16 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 16 e^{4 x} \cdot 4

Simplify

= 64 e^{4 x}

\frac{d}{d x} (\frac{x}{3} - \frac{3}{x})

(x + 1) \frac{d y}{d x} + y = ln (x)

\int_{0}^{2} 4^{- x} d x

y^{^{'}} = \frac{1}{x + y}

\frac{d}{d x} ((3 x^{2} - 4 x)^{2})

What is the derivative of 16e^{4x} ?
The derivative of 16e^{4x} is 64e^{4x}
What is the first derivative of 16e^{4x} ?
The first derivative of 16e^{4x} is 64e^{4x}