What is the solution for (x+1)(dy)/(dx)+y=ln(x) ?

The solution for (x+1)(dy)/(dx)+y=ln(x) is y=(xln(x))/(x+1)-x/(x+1)+(c_{1})/(x+1)

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(x+1)(dy)/(dx)+y=ln(x)

(x + 1) \frac{d y}{d x} + y = ln (x)

y = \frac{x ln ( x )}{x + 1} - \frac{x}{x + 1} + \frac{c _{1}}{x + 1}

Solution steps

(x + 1) \frac{d y}{d x} + y = ln (x)

Solve linear ODE:

y = \frac{x ln ( x )}{x + 1} - \frac{x}{x + 1} + \frac{c _{1}}{x + 1}

y = \frac{x ln ( x )}{x + 1} - \frac{x}{x + 1} + \frac{c _{1}}{x + 1}

\int_{0}^{2} 4^{- x} d x

y^{^{'}} = \frac{1}{x + y}

\frac{d}{d x} ((3 x^{2} - 4 x)^{2})

x^{2} + 3 x + 1

f (t) = 7 t + 3

What is the solution for (x+1)(dy)/(dx)+y=ln(x) ?
The solution for (x+1)(dy)/(dx)+y=ln(x) is y=(xln(x))/(x+1)-x/(x+1)+(c_{1})/(x+1)