What is the integral of (2x+1)e^{x^2+x} ?

The integral of (2x+1)e^{x^2+x} is e^{x^2+x}+C

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integral of (2x+1)e^{x^2+x}

\int (2 x + 1) e^{x^{2} + x} d x

e^{x^{2} + x} + C

Solution steps

\int (2 x + 1) e^{x^{2} + x} d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = x^{2} + x

= e^{x^{2} + x}

Add a constant to the solution

= e^{x^{2} + x} + C

x \to 1 lim (\frac{5}{x - 1})

\int 36 + cos (x) d x

\int \frac{tan ( x )}{sec ^{2} ( x )} d x

\frac{2 x ^{5} + 7}{x ^{3}}

\frac{( x ^{2} )}{x - 7}

What is the integral of (2x+1)e^{x^2+x} ?
The integral of (2x+1)e^{x^2+x} is e^{x^2+x}+C