What is the integral of 36+cos(x) ?

The integral of 36+cos(x) is 36x+sin(x)+C

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integral of 36+cos(x)

\int 36 + cos (x) d x

36 x + sin (x) + C

Solution steps

\int 36 + cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 36 d x + \int cos (x) d x

\int 36 d x = 36 x

\int cos (x) d x = sin (x)

= 36 x + sin (x)

Add a constant to the solution

= 36 x + sin (x) + C

\int \frac{tan ( x )}{sec ^{2} ( x )} d x

\frac{2 x ^{5} + 7}{x ^{3}}

\frac{( x ^{2} )}{x - 7}

\frac{x}{x ^{4} + 1}

\frac{\partial}{\partial u} (4 u cos (v))