What is the integral of te^{-t} ?

The integral of te^{-t} is -e^{-t}t-e^{-t}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of te^{-t}

\int t e^{- t} d t

- e^{- t} t - e^{- t} + C

Solution steps

\int t e^{- t} d t

Apply Integration By Parts

= - e^{- t} t - \int - e^{- t} d t

\int - e^{- t} d t = e^{- t}

= - e^{- t} t - e^{- t}

Add a constant to the solution

= - e^{- t} t - e^{- t} + C

y^{^{''}} + 4 y^{^{'}} = - 6 x - 3

\frac{\partial}{\partial x} (- sin (x) cos (y))

n = 2 \sum \infty \frac{1}{( n ^{3} - n )}

\frac{d y}{d x} = \frac{1}{3} y (8 - y), y (0) = 1

2 x^{4} y^{^{'}} = k