What is the derivative of f(x)=5x^2cos(x)+4x ?

The derivative of f(x)=5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4

What is the first derivative of f(x)=5x^2cos(x)+4x ?

The first derivative of f(x)=5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4

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derivative of

f (x) = 5 x^{2} cos (x) + 4 x

5 (2 x cos (x) - x^{2} sin (x)) + 4

Solution steps

\frac{d}{d x} (5 x^{2} cos (x) + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{2} cos (x)) + \frac{d}{d x} (4 x)

\frac{d}{d x} (5 x^{2} cos (x)) = 5 (2 x cos (x) - x^{2} sin (x))

\frac{d}{d x} (4 x) = 4

= 5 (2 x cos (x) - x^{2} sin (x)) + 4

\int_{1}^{- 1} 3 e^{x} d x

t^{2} y^{^{''}} + 2 t y^{^{'}} - 12 y = 0

f (x) = 9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4}

3 x + sin (5 x)

y = \frac{x}{4 x + 7}

What is the derivative of f(x)=5x^2cos(x)+4x ?
The derivative of f(x)=5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4
What is the first derivative of f(x)=5x^2cos(x)+4x ?
The first derivative of f(x)=5x^2cos(x)+4x is 5(2xcos(x)-x^2sin(x))+4