What is the solution for x^2(dy)/(dx)-2xy=5y^4,y(1)= 1/3 ?

The solution for x^2(dy)/(dx)-2xy=5y^4,y(1)= 1/3 is y=(x^2)/(\sqrt[3]{3(-x^5+10))}

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x^2(dy)/(dx)-2xy=5y^4,y(1)= 1/3

x^{2} \frac{d y}{d x} - 2 x y = 5 y^{4}, y (1) = \frac{1}{3}

Solution steps

x^{2} \frac{d y}{d x} - 2 x y = 5 y^{4}

Solve Bernoulli ODE:

\int (\frac{sec ( x ) + cos ( x )}{2 cos ( x )}) d x

\frac{d}{d x} ((2 x + 9)^{2})

y = 3 + lo g_{2} (x)

d y = x^{2} d x

\frac{d}{d x} (\frac{2 x + 5}{2 x - 5})

What is the solution for x^2(dy)/(dx)-2xy=5y^4,y(1)= 1/3 ?
The solution for x^2(dy)/(dx)-2xy=5y^4,y(1)= 1/3 is y=(x^2)/(\sqrt[3]{3(-x^5+10))}