What is the integral of ((sec(x)+cos(x))/(2cos(x))) ?

The integral of ((sec(x)+cos(x))/(2cos(x))) is 1/2 (tan(x)+x)+C

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integral of ((sec(x)+cos(x))/(2cos(x)))

\int (\frac{sec ( x ) + cos ( x )}{2 cos ( x )}) d x

\frac{1}{2} (tan (x) + x) + C

Solution steps

\int \frac{sec ( x ) + cos ( x )}{2 cos ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{sec ( x ) + cos ( x )}{cos ( x )} d x

Expand

\frac{sec ( x ) + cos ( x )}{cos ( x )} : \frac{sec ( x )}{cos ( x )} + 1

= \frac{1}{2} \cdot \int \frac{sec ( x )}{cos ( x )} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int \frac{sec ( x )}{cos ( x )} d x + \int 1 d x)

\int \frac{sec ( x )}{cos ( x )} d x = tan (x)

\int 1 d x = x

= \frac{1}{2} (tan (x) + x)

Add a constant to the solution

= \frac{1}{2} (tan (x) + x) + C

\frac{d}{d x} ((2 x + 9)^{2})

y = 3 + lo g_{2} (x)

d y = x^{2} d x

\frac{d}{d x} (\frac{2 x + 5}{2 x - 5})

\frac{\partial}{\partial x} (26 - x^{2} - y^{2})

What is the integral of ((sec(x)+cos(x))/(2cos(x))) ?
The integral of ((sec(x)+cos(x))/(2cos(x))) is 1/2 (tan(x)+x)+C