What is (\partial)/(\partial x)((8y)/(x^5)) ?

The answer to (\partial)/(\partial x)((8y)/(x^5)) is -(40y)/(x^6)

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(\partial)/(\partial x)((8y)/(x^5))

\frac{\partial}{\partial x} (\frac{8 y}{x ^{5}})

- \frac{40 y}{x ^{6}}

Solution steps

\frac{\partial}{\partial x} (\frac{8 y}{x ^{5}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 y \frac{\partial}{\partial x} (\frac{1}{x ^{5}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 y \frac{\partial}{\partial x} (x^{- 5})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 y (- 5 x^{- 5 - 1})

Simplify

8 y (- 5 x^{- 5 - 1}) : - \frac{40 y}{x ^{6}}

= - \frac{40 y}{x ^{6}}

f (x) = \frac{1}{2 x + 1}

\frac{\partial}{\partial x} (\frac{6 x y ^{2}}{x ^{2} + y ^{4}})

f (x) = \frac{2 x - 4}{x}, at x = 4

\int - \frac{4}{25} x + 58 d x

\int (\frac{2 x - 5}{7}) d x

What is (\partial)/(\partial x)((8y)/(x^5)) ?
The answer to (\partial)/(\partial x)((8y)/(x^5)) is -(40y)/(x^6)