What is the derivative of 3-3x^2 ?

The derivative of 3-3x^2 is -6x

What is the first derivative of 3-3x^2 ?

The first derivative of 3-3x^2 is -6x

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\frac{d}{d x} (3 - 3 x^{2})

- 6 x

Solution steps

\frac{d}{d x} (3 - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 - 6 x

Simplify

= - 6 x

f (x) = - \frac{7}{( x + 4 ) ^{2}}

f (t) = (1) (t^{3})

\frac{d}{d x} (\frac{1}{16 x ^{4}})

- 3 y^{^{'}} + \frac{3 y}{x} = x y^{4}

\int \frac{x}{( x ^{2} - 3 ) ^{3}} d x