What is the tangent of 4x^2-2x,\at x=-1 ?

The tangent of 4x^2-2x,\at x=-1 is y=-10x-4

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tangent of 4x^2-2x,\at x=-1

tangent of

4 x^{2} - 2 x, at x = - 1

y = - 10 x - 4

Solution steps

Find the tangent point:

(- 1, 6)

Find the slope of

y = 4 x^{2} - 2 x : \frac{d y}{d x} = 8 x - 2

Compute the slope of

y = 4 x^{2} - 2 x

x = - 1 : m = - 10

Find the line with slope m=

- 10

and passing through

(- 1, 6) : y = - 10 x - 4

y = - 10 x - 4

\frac{1}{( 1 + x ) ^{2}}

x y^{^{'}} = 2 x^{2} + y, y (1) = 3

\frac{d}{d x} (cos (3 ln (x)))

e^{x} - 5 x^{4}

\int \frac{4}{( x + 2 ) ^{2}} d x

What is the tangent of 4x^2-2x,\at x=-1 ?
The tangent of 4x^2-2x,\at x=-1 is y=-10x-4