What is the derivative of-8sin(t) ?

The derivative of-8sin(t) is -8cos(t)

What is the first derivative of-8sin(t) ?

The first derivative of-8sin(t) is -8cos(t)

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derivative of

- 8 sin (t)

- 8 cos (t)

Solution steps

\frac{d}{d t} (- 8 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d t} (sin (t))

Apply the common derivative:

\frac{d}{d t} (sin (t)) = cos (t)

= - 8 cos (t)

(12 y^{2} - x y) d x + x^{2} d y = 0

f (x) = \frac{3}{x}, (8, \frac{3}{8})

\int \frac{4}{5 - 3 x} d x

\frac{\partial}{\partial θ} (r cos (θ))

x^{\frac{1}{x}}

What is the derivative of-8sin(t) ?
The derivative of-8sin(t) is -8cos(t)
What is the first derivative of-8sin(t) ?
The first derivative of-8sin(t) is -8cos(t)