What is the tangent of f(x)= 3/x ,(8, 3/8) ?

The tangent of f(x)= 3/x ,(8, 3/8) is y=-3/64 x+3/4

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tangent of f(x)= 3/x ,(8, 3/8)

tangent of

f (x) = \frac{3}{x}, (8, \frac{3}{8})

y = - \frac{3}{64} x + \frac{3}{4}

Solution steps

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

f (x) = \frac{3}{x}

(8, \frac{3}{8}) : m = - \frac{3}{64}

Find the line with slope m=

- \frac{3}{64}

and passing through

(8, \frac{3}{8}) : y = - \frac{3}{64} x + \frac{3}{4}

y = - \frac{3}{64} x + \frac{3}{4}

\int \frac{4}{5 - 3 x} d x

\frac{\partial}{\partial θ} (r cos (θ))

x^{\frac{1}{x}}

\frac{d y}{d t} = 2 (y^{2} - y) t

\int 5 x + 4 d x

What is the tangent of f(x)= 3/x ,(8, 3/8) ?
The tangent of f(x)= 3/x ,(8, 3/8) is y=-3/64 x+3/4