What is the solution for (12y^2-xy)dx+x^2dy=0 ?

The solution for (12y^2-xy)dx+x^2dy=0 is y= x/(12ln(x)+c_{1)}

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(12y^2-xy)dx+x^2dy=0

(12 y^{2} - x y) d x + x^{2} d y = 0

y = \frac{x}{12 ln ( x ) + c _{1}}

Solution steps

(12 y^{2} - x y) d x + x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{x}{12 ln ( x ) + c _{1}}

y = \frac{x}{12 ln ( x ) + c _{1}}

f (x) = \frac{3}{x}, (8, \frac{3}{8})

\int \frac{4}{5 - 3 x} d x

\frac{\partial}{\partial θ} (r cos (θ))

x^{\frac{1}{x}}

\frac{d y}{d t} = 2 (y^{2} - y) t

What is the solution for (12y^2-xy)dx+x^2dy=0 ?
The solution for (12y^2-xy)dx+x^2dy=0 is y= x/(12ln(x)+c_{1)}