What is the integral of cos(4y) ?

The integral of cos(4y) is 1/4 sin(4y)+C

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integral of cos(4y)

\int cos (4 y) d y

\frac{1}{4} sin (4 y) + C

Solution steps

\int cos (4 y) d y

Apply u-substitution

: \int cos (u) \frac{1}{4} d u

= \int cos (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{4} sin (u)

Substitute back

u = 4 y

= \frac{1}{4} sin (4 y)

Add a constant to the solution

= \frac{1}{4} sin (4 y) + C

\int x^{2} x^{2} - 25 d x

y^{^{'}} + \frac{1}{t} y = 0

n = 1 \sum \infty (\frac{x}{n})^{n}

y = x^{3} - x, (1, 0)

\frac{d}{d x} (\frac{x}{x ^{2} - 15})