What is the integral of xsin^2(7x) ?

The integral of xsin^2(7x) is 1/392 (98x^2-14xsin(14x)-cos(14x))+C

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integral of xsin^2(7x)

\int x sin^{2} (7 x) d x

\frac{1}{392} (98 x^{2} - 14 x sin (14 x) - cos (14 x)) + C

Solution steps

\int x sin^{2} (7 x) d x

Rewrite using trig identities

= \int \frac{1}{2} x (1 - cos (14 x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x (1 - cos (14 x)) d x

Apply Integration By Parts

: x (x - \frac{1}{14} sin (14 x)) - \int x - \frac{1}{14} sin (14 x) d x

= \frac{1}{2} (x (x - \frac{1}{14} sin (14 x)) - \int x - \frac{1}{14} sin (14 x) d x)

\int x - \frac{1}{14} sin (14 x) d x = \frac{x ^{2}}{2} + \frac{1}{196} cos (14 x)

= \frac{1}{2} (x (x - \frac{1}{14} sin (14 x)) - (\frac{x ^{2}}{2} + \frac{1}{196} cos (14 x)))

Simplify

\frac{1}{2} (x (x - \frac{1}{14} sin (14 x)) - (\frac{x ^{2}}{2} + \frac{1}{196} cos (14 x))) : \frac{1}{392} (98 x^{2} - 14 x sin (14 x) - cos (14 x))

= \frac{1}{392} (98 x^{2} - 14 x sin (14 x) - cos (14 x))

Add a constant to the solution

= \frac{1}{392} (98 x^{2} - 14 x sin (14 x) - cos (14 x)) + C

f (x) = \frac{2}{x}, (3, \frac{2}{3})

f (x) = \frac{x + 6}{x - 4}

1 + x

y = (4 x - 1)^{2}

\frac{d}{d x} ((3 x + 4) (- 3 + 2 x))

What is the integral of xsin^2(7x) ?
The integral of xsin^2(7x) is 1/392 (98x^2-14xsin(14x)-cos(14x))+C