What is area 2x^3-6x^2-2x+6,-x^3+3x^2+x-3 ?

The answer to area 2x^3-6x^2-2x+6,-x^3+3x^2+x-3 is 24

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area 2x^3-6x^2-2x+6,-x^3+3x^2+x-3

area

2 x^{3} - 6 x^{2} - 2 x + 6, - x^{3} + 3 x^{2} + x - 3

24

Solution steps

Apply the area formula:

\int_{- 1}^{3} 2 x^{3} - 6 x^{2} - 2 x + 6 - (- x^{3} + 3 x^{2} + x - 3) d x

Solve

\int_{- 1}^{3} 2 x^{3} - 6 x^{2} - 2 x + 6 - (- x^{3} + 3 x^{2} + x - 3) d x : 24

The area is:

= 24

y = 5 cos (7 x), y = 5 - 5 cos (7 x)

\int_{0}^{\frac{π}{16}} cos (8 x) d x

\int_{0}^{4} π (\frac{20 - 5 x}{4})^{2} d x

y = 4 x^{2} + 1

\int 2 x^{3} e^{x^{2}} d x

What is area 2x^3-6x^2-2x+6,-x^3+3x^2+x-3 ?
The answer to area 2x^3-6x^2-2x+6,-x^3+3x^2+x-3 is 24