What is area y=5cos(7x),y=5-5cos(7x) ?

The answer to area y=5cos(7x),y=5-5cos(7x) is (10sqrt(3))/7+(20pi)/(21)

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area y=5cos(7x),y=5-5cos(7x)

area

y = 5 cos (7 x), y = 5 - 5 cos (7 x)

\frac{10 3}{7} + \frac{20 π}{21}

Decimal Notation

5.46635 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{21}}^{\frac{5 π}{21}} ∣ 5 cos (7 x) - (5 - 5 cos (7 x)) ∣ d x

Solve

\int_{\frac{π}{21}}^{\frac{5 π}{21}} ∣ 5 cos (7 x) - (5 - 5 cos (7 x)) ∣ d x : \frac{10 3}{7} + \frac{20 π}{21}

The area is:

= \frac{10 3}{7} + \frac{20 π}{21}

\int_{0}^{\frac{π}{16}} cos (8 x) d x

\int_{0}^{4} π (\frac{20 - 5 x}{4})^{2} d x

y = 4 x^{2} + 1

\int 2 x^{3} e^{x^{2}} d x

\frac{d}{d x} (x + y - 1)

What is area y=5cos(7x),y=5-5cos(7x) ?
The answer to area y=5cos(7x),y=5-5cos(7x) is (10sqrt(3))/7+(20pi)/(21)