What is the derivative of y=4x^2+1 ?

The derivative of y=4x^2+1 is 8x

What is the first derivative of y=4x^2+1 ?

The first derivative of y=4x^2+1 is 8x

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derivative of

y = 4 x^{2} + 1

8 x

Solution steps

\frac{d}{d x} (4 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (1) = 0

= 8 x + 0

Simplify

= 8 x

\int 2 x^{3} e^{x^{2}} d x

\frac{d}{d x} (x + y - 1)

\int (\frac{1}{2 x}) d x

y = 3 x, x = 0, x = 4

2^{y}

What is the derivative of y=4x^2+1 ?
The derivative of y=4x^2+1 is 8x
What is the first derivative of y=4x^2+1 ?
The first derivative of y=4x^2+1 is 8x