What is (\partial)/(\partial x)(y^2zcos(x)) ?

The answer to (\partial)/(\partial x)(y^2zcos(x)) is -y^2zsin(x)

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(\partial)/(\partial x)(y^2zcos(x))

\frac{\partial}{\partial x} (y^{2} z cos (x))

- y^{2} z sin (x)

Solution steps

\frac{\partial}{\partial x} (y^{2} z cos (x))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} z \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= y^{2} z (- sin (x))

Simplify

= - y^{2} z sin (x)

\frac{\partial}{\partial x} (\frac{x ^{3} y ^{3}}{3})

\frac{\partial}{\partial x} (\frac{g ( x )}{x} - \frac{h ( x )}{x})

\int sec^{7} (x) tan (x) d x

\int e^{t a n (v)} sec^{2} (v) d v

\frac{d}{d x} ((e^{- t^{2}}) x^{2})

What is (\partial)/(\partial x)(y^2zcos(x)) ?
The answer to (\partial)/(\partial x)(y^2zcos(x)) is -y^2zsin(x)