What is the derivative of (x^3+1^2) ?

The derivative of (x^3+1^2) is 6x^2(x^3+1)

What is the first derivative of (x^3+1^2) ?

The first derivative of (x^3+1^2) is 6x^2(x^3+1)

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\frac{d}{d x} ((x^{3} + 1)^{2})

6 x^{2} (x^{3} + 1)

Solution steps

\frac{d}{d x} ((x^{3} + 1)^{2})

Apply the chain rule:

2 (x^{3} + 1) \frac{d}{d x} (x^{3} + 1)

= 2 (x^{3} + 1) \frac{d}{d x} (x^{3} + 1)

\frac{d}{d x} (x^{3} + 1) = 3 x^{2}

= 2 (x^{3} + 1) \cdot 3 x^{2}

Simplify

= 6 x^{2} (x^{3} + 1)

y = (4 - 3 x^{2})^{3}

y^{^{'}} + 2 y = 10

\frac{d}{d x} (\frac{1}{27} (2 x - 1)^{3} (6 - 3 x) + 1)

\int_{0}^{\frac{π}{4}} sin (4 x) d x

\frac{- 3}{( s - 1 ) ^{2}}

What is the derivative of (x^3+1^2) ?
The derivative of (x^3+1^2) is 6x^2(x^3+1)
What is the first derivative of (x^3+1^2) ?
The first derivative of (x^3+1^2) is 6x^2(x^3+1)