What is the derivative of sqrt(u+1)(1-8u^2)^7 ?

The derivative of sqrt(u+1)(1-8u^2)^7 is ((1-8u^2)^7)/(2sqrt(u+1))-112u(1-8u^2)^6sqrt(u+1)

What is the first derivative of sqrt(u+1)(1-8u^2)^7 ?

The first derivative of sqrt(u+1)(1-8u^2)^7 is ((1-8u^2)^7)/(2sqrt(u+1))-112u(1-8u^2)^6sqrt(u+1)

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derivative of

u + 1 (1 - 8 u^{2})^{7}

\frac{( 1 - 8 u ^{2} ) ^{7}}{2 u + 1} - 112 u (1 - 8 u^{2})^{6} u + 1

Solution steps

\frac{d}{d u} (u + 1 (1 - 8 u^{2})^{7})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = u + 1, g = (1 - 8 u^{2})^{7}

= \frac{d}{d u} (u + 1) (1 - 8 u^{2})^{7} + \frac{d}{d u} ((1 - 8 u^{2})^{7}) u + 1

\frac{d}{d u} (u + 1) = \frac{1}{2 u + 1}

\frac{d}{d u} ((1 - 8 u^{2})^{7}) = - 112 u (1 - 8 u^{2})^{6}

= \frac{1}{2 u + 1} (1 - 8 u^{2})^{7} + (- 112 u (1 - 8 u^{2})^{6}) u + 1

Simplify

\frac{1}{2 u + 1} (1 - 8 u^{2})^{7} + (- 112 u (1 - 8 u^{2})^{6}) u + 1 : \frac{( 1 - 8 u ^{2} ) ^{7}}{2 u + 1} - 112 u (1 - 8 u^{2})^{6} u + 1

= \frac{( 1 - 8 u ^{2} ) ^{7}}{2 u + 1} - 112 u (1 - 8 u^{2})^{6} u + 1

e^{- b t}

x \to - 2 - lim (\frac{1 - x}{x ^{3} + 8})

\frac{d}{d x} ((1 + i)^{x})

\frac{\partial}{\partial x} ((4 x + 8) ln (6 x y))

\frac{d}{d x} (4 e^{- 3 x})

What is the derivative of sqrt(u+1)(1-8u^2)^7 ?
The derivative of sqrt(u+1)(1-8u^2)^7 is ((1-8u^2)^7)/(2sqrt(u+1))-112u(1-8u^2)^6sqrt(u+1)
What is the first derivative of sqrt(u+1)(1-8u^2)^7 ?
The first derivative of sqrt(u+1)(1-8u^2)^7 is ((1-8u^2)^7)/(2sqrt(u+1))-112u(1-8u^2)^6sqrt(u+1)