What is the tangent of y=4-x^2 ?

The tangent of y=4-x^2 is y=-2a_{0}x+4+a_{0}^2

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tangent of y=4-x^2

tangent of

y = 4 - x^{2}

y = - 2 a_{0} x + 4 + a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 4 - a_{0}^{2})

Find the slope of

y = 4 - x^{2} : \frac{d y}{d x} = - 2 x

Compute the slope of

y = 4 - x^{2}

x = a_{0} : m = - 2 a_{0}

Find the line with slope m=

- 2 a_{0}

and passing through

(a_{0}, 4 - a_{0}^{2}) : y = - 2 a_{0} x + 4 + a_{0}^{2}

y = - 2 a_{0} x + 4 + a_{0}^{2}

x \to 0 lim (\frac{x}{∣ x ∣} sin (x))

\frac{\partial}{\partial r} (2 π r^{2} + 2 π r h)

\frac{d}{d x} (2 tan^{2} (x))

\frac{d}{d x} (6 sin (x) cos (x))