What is (\partial)/(\partial x)(e^{2x}-xcos(t)) ?

The answer to (\partial)/(\partial x)(e^{2x}-xcos(t)) is e^{2x}*2-cos(t)

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(\partial)/(\partial x)(e^{2x}-xcos(t))

\frac{\partial}{\partial x} (e^{2 x} - x cos (t))

e^{2 x} \cdot 2 - cos (t)

Solution steps

\frac{\partial}{\partial x} (e^{2 x} - x cos (t))

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{2 x}) - \frac{\partial}{\partial x} (x cos (t))

\frac{\partial}{\partial x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{\partial}{\partial x} (x cos (t)) = cos (t)

= e^{2 x} \cdot 2 - cos (t)

5 \frac{d y}{d x} + 30 y = 6

f (x) = \frac{1}{x ^{2}}

\frac{d}{d x} (x^{3} - 3 x^{2} + 4)

\int \frac{1}{csc ( 5 x ) cos ( 5 x )} d x

\frac{d}{d x} (e^{2 x + y})

What is (\partial)/(\partial x)(e^{2x}-xcos(t)) ?
The answer to (\partial)/(\partial x)(e^{2x}-xcos(t)) is e^{2x}*2-cos(t)