What is the solution for (d^2x)/(dt)+2(dx)/(dt)+x=1 ?

The solution for (d^2x)/(dt)+2(dx)/(dt)+x=1 is x=-e^{(-t-c_{1})/3}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2x)/(dt)+2(dx)/(dt)+x=1

\frac{d ^{2} x}{d t} + 2 \frac{d x}{d t} + x = 1

x = - e^{\frac{- t - c _{1}}{3}} + 1

Solution steps

\frac{d x}{d t} + 2 \frac{d x}{d t} + x = 1

Solve separable ODE:

x = - e^{\frac{- t - c _{1}}{3}} + 1

x = - e^{\frac{- t - c _{1}}{3}} + 1

\int 5 + x^{2} d x

y = 8 x, y = 4 x^{2}

\frac{\partial}{\partial y} (2 e^{x} ln (y))

\frac{\partial}{\partial x} (4 x y + yz + 3 x z - 32)

\frac{d}{d x} (x^{6} e^{2 x^{3}})

What is the solution for (d^2x)/(dt)+2(dx)/(dt)+x=1 ?
The solution for (d^2x)/(dt)+2(dx)/(dt)+x=1 is x=-e^{(-t-c_{1})/3}+1