What is the integral of (-1/x+7e^x) ?

The integral of (-1/x+7e^x) is -ln|x|+7e^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (-1/x+7e^x)

\int (- \frac{1}{x} + 7 e^{x}) d x

- ln ∣ x ∣ + 7 e^{x} + C

Solution steps

\int - \frac{1}{x} + 7 e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{1}{x} d x + \int 7 e^{x} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int 7 e^{x} d x = 7 e^{x}

= - ln ∣ x ∣ + 7 e^{x}

Add a constant to the solution

= - ln ∣ x ∣ + 7 e^{x} + C

\frac{d}{d x} (6 + x^{2})

\int 2 x + 1 d x

\int 3^{x} sin (x) d x

\frac{\partial}{\partial y} (y cos (x ln (y)))

\int_{0}^{2} 1 + 3 x^{2} d x

What is the integral of (-1/x+7e^x) ?
The integral of (-1/x+7e^x) is -ln|x|+7e^x+C