What is the solution for y^{''}+4y^'+4y=0,y(1)=0,y^'(1)=1 ?

The solution for y^{''}+4y^'+4y=0,y(1)=0,y^'(1)=1 is y=-e^{2-2t}+e^{2-2t}t

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y^{''}+4y^'+4y=0,y(1)=0,y^'(1)=1

y^{^{''}} + 4 y^{^{'}} + 4 y = 0, y (1) = 0, y^{^{'}} (1) = 1

y = - e^{2 - 2 t} + e^{2 - 2 t} t

Solution steps

y^{''} (t) + 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = - e^{2 - 2 t} + e^{2 - 2 t} t

y = - e^{2 - 2 t} + e^{2 - 2 t} t

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What is the solution for y^{''}+4y^'+4y=0,y(1)=0,y^'(1)=1 ?
The solution for y^{''}+4y^'+4y=0,y(1)=0,y^'(1)=1 is y=-e^{2-2t}+e^{2-2t}t