What is the derivative of 0.001x^3+0.2x^2+36x+300 ?

The derivative of 0.001x^3+0.2x^2+36x+300 is 0.003x^2+0.4x+36

What is the first derivative of 0.001x^3+0.2x^2+36x+300 ?

The first derivative of 0.001x^3+0.2x^2+36x+300 is 0.003x^2+0.4x+36

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derivative of

0.001 x^{3} + 0.2 x^{2} + 36 x + 300

0.003 x^{2} + 0.4 x + 36

Solution steps

\frac{d}{d x} (0.001 x^{3} + 0.2 x^{2} + 36 x + 300)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.001 x^{3}) + \frac{d}{d x} (0.2 x^{2}) + \frac{d}{d x} (36 x) + \frac{d}{d x} (300)

\frac{d}{d x} (0.001 x^{3}) = 0.003 x^{2}

\frac{d}{d x} (0.2 x^{2}) = 0.4 x

\frac{d}{d x} (36 x) = 36

\frac{d}{d x} (300) = 0

= 0.003 x^{2} + 0.4 x + 36 + 0

Simplify

= 0.003 x^{2} + 0.4 x + 36

\int e^{- x} cos (- x) d x

\frac{d y}{d x} = e^{8 x - 8 y}

y = \frac{7 x}{3 + x ^{2}}, (2, 2)

\frac{\partial}{\partial x} (3 y uxu v^{3} - 2)

\int \frac{1}{x - 4} d x

What is the derivative of 0.001x^3+0.2x^2+36x+300 ?
The derivative of 0.001x^3+0.2x^2+36x+300 is 0.003x^2+0.4x+36
What is the first derivative of 0.001x^3+0.2x^2+36x+300 ?
The first derivative of 0.001x^3+0.2x^2+36x+300 is 0.003x^2+0.4x+36