What is the tangent of y=(7x)/(3+x^2),(2,2) ?

The tangent of y=(7x)/(3+x^2),(2,2) is y=-1/7 x+16/7

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tangent of y=(7x)/(3+x^2),(2,2)

tangent of

y = \frac{7 x}{3 + x ^{2}}, (2, 2)

y = - \frac{1}{7} x + \frac{16}{7}

Solution steps

Find the slope of

y = \frac{7 x}{3 + x ^{2}} : \frac{d y}{d x} = \frac{7 ( 3 - x ^{2} )}{( 3 + x ^{2} ) ^{2}}

Compute the slope of

y = \frac{7 x}{3 + x ^{2}}

(2, 2) : m = - \frac{1}{7}

Find the line with slope m=

- \frac{1}{7}

and passing through

(2, 2) : y = - \frac{1}{7} x + \frac{16}{7}

y = - \frac{1}{7} x + \frac{16}{7}

\frac{\partial}{\partial x} (3 y uxu v^{3} - 2)

\int \frac{1}{x - 4} d x

n = 8 \sum \infty \frac{1}{n} sin (\frac{1}{n})

y^{^{'}} = \frac{t y}{t + 1}, y (4) = 1

What is the tangent of y=(7x)/(3+x^2),(2,2) ?
The tangent of y=(7x)/(3+x^2),(2,2) is y=-1/7 x+16/7