What is the d/(dt)(e^{t^2}) ?

The d/(dt)(e^{t^2}) is e^{t^2}*2t

What is the first d/(dt)(e^{t^2}) ?

The first d/(dt)(e^{t^2}) is e^{t^2}*2t

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\frac{d}{d t} (e^{t^{2}})

e^{t^{2}} \cdot 2 t

Solution steps

\frac{d}{d t} (e^{t^{2}})

Apply the chain rule:

e^{t^{2}} \frac{d}{d t} (t^{2})

= e^{t^{2}} \frac{d}{d t} (t^{2})

\frac{d}{d t} (t^{2}) = 2 t

= e^{t^{2}} \cdot 2 t

\int \frac{( 7 x ^{2} + 2 x - 7 )}{x ^{3} - x} d x

\frac{\partial}{\partial x} (3 sin (x y))

\frac{d y}{d x} - 2 y = 4

(7 x^{2} - 14 x + 14) e^{x}

\frac{\partial}{\partial y} (y^{2} sin (x))