What is the derivative of f(x)=x^2+x-3 ?

The derivative of f(x)=x^2+x-3 is 2x+1

What is the first derivative of f(x)=x^2+x-3 ?

The first derivative of f(x)=x^2+x-3 is 2x+1

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derivative of

f (x) = x^{2} + x - 3

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

y^{^{'}} + y = x^{2}

(17 + x^{2}) y^{^{'}} - 2 x y = 0

\frac{d}{d x} (\frac{cos ( x )}{1 + x ^{2}})

x \to 0 lim (\frac{1}{2 x ^{2}})

\frac{d ^{2}}{d x ^{2}} (cos^{2} (3 π x))

What is the derivative of f(x)=x^2+x-3 ?
The derivative of f(x)=x^2+x-3 is 2x+1
What is the first derivative of f(x)=x^2+x-3 ?
The first derivative of f(x)=x^2+x-3 is 2x+1