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Popular >

y^'+y=x^2

Solution

y^{^{'}} + y = x^{2}

Solution

y = x^{2} - 2 (x - 1) + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y = x^{2}

Solve linear ODE:

y = x^{2} - 2 (x - 1) + \frac{c _{1}}{e ^{x}}

y = x^{2} - 2 (x - 1) + \frac{c _{1}}{e ^{x}}

Popular Examples

(17+x^2)y^'-2xy=0

(17 + x^{2}) y^{^{'}} - 2 x y = 0

derivative of (cos(x)/(sqrt(1+x^2)))

\frac{d}{d x} (\frac{cos ( x )}{1 + x ^{2}})

limit as x approaches 0 of 1/(2x^2)

x \to 0 lim (\frac{1}{2 x ^{2}})

(d^2)/(dx^2)(cos^2(3pix))

\frac{d ^{2}}{d x ^{2}} (cos^{2} (3 π x))

integral of x^{28}e^{x^{29}}

\int x^{28} e^{x^{29}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=x^2 ?
The solution for y^'+y=x^2 is y=x^2-2(x-1)+(c_{1})/(e^x)