What is the solution for y^'-2xy=1 ?

The solution for y^'-2xy=1 is y=(sqrt(pi)\erf(x))/(2e^{-x^2)}+c_{1}e^{x^2}

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y^'-2xy=1

y^{^{'}} - 2 x y = 1

y = \frac{π erf ( x )}{2 e ^{- x^{2}}} + c_{1} e^{x^{2}}

Solution steps

y^{'} (x) - 2 x y = 1

Solve linear ODE:

y = \frac{π erf ( x )}{2 e ^{- x^{2}}} + c_{1} e^{x^{2}}

y = \frac{π erf ( x )}{2 e ^{- x^{2}}} + c_{1} e^{x^{2}}

\frac{\partial}{\partial x} (2 x^{3} + 2 x y^{3})

\int \frac{1}{16 x} d x

\frac{\partial}{\partial x} (y^{3} sin (3 x))

g (x) = \frac{( π ^{2} )}{x ^{2} + 4 x}

\frac{d}{d x} (sec (x) - x)

What is the solution for y^'-2xy=1 ?
The solution for y^'-2xy=1 is y=(sqrt(pi)\erf(x))/(2e^{-x^2)}+c_{1}e^{x^2}