What is the derivative of ln(2x+2) ?

The derivative of ln(2x+2) is 1/(x+1)

What is the first derivative of ln(2x+2) ?

The first derivative of ln(2x+2) is 1/(x+1)

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\frac{d}{d x} (ln (2 x + 2))

\frac{1}{x + 1}

Solution steps

\frac{d}{d x} (ln (2 x + 2))

Apply the chain rule:

\frac{1}{2 x + 2} \frac{d}{d x} (2 x + 2)

= \frac{1}{2 x + 2} \frac{d}{d x} (2 x + 2)

\frac{d}{d x} (2 x + 2) = 2

= \frac{1}{2 x + 2} \cdot 2

Simplify

\frac{1}{2 x + 2} \cdot 2 : \frac{1}{x + 1}

= \frac{1}{x + 1}

\frac{\partial}{\partial x} ((x^{2} - 1) \cdot x^{0})

\frac{\partial}{\partial x} (3 x^{2} + 6 y)

\frac{d}{d x} (- 0.5 x^{2})

g (x) = x^{5} + \frac{1}{x ^{5}}

x \to - 3 + lim (\frac{1}{x ^{2} - 9})

What is the derivative of ln(2x+2) ?
The derivative of ln(2x+2) is 1/(x+1)
What is the first derivative of ln(2x+2) ?
The first derivative of ln(2x+2) is 1/(x+1)