What is the sum from n=0 to infinity of e^{-1} ?

The sum from n=0 to infinity of e^{-1} is diverges

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sum from n=0 to infinity of e^{-1}

n = 0 \sum \infty e^{- 1}

diverges

Solution steps

n = 0 \sum \infty e^{- 1}

Every infinite sum of a non-zero constant diverges

= diverges

\int_{- 1}^{1} x e^{x} d x

\frac{d}{d x} (ln (x^{2} + 3 x))

\frac{d}{d x} (5 (1 - e^{- 2 x}))

\frac{d}{d x} (x^{2} + y^{2} - 4)

x \to - 1 lim (\frac{x ^{2} + 1}{x + 1})

What is the sum from n=0 to infinity of e^{-1} ?
The sum from n=0 to infinity of e^{-1} is diverges