What is the solution for 10(dy)/(dx)+20y=12 ?

The solution for 10(dy)/(dx)+20y=12 is y=-(e^{-2x-c_{1}})/5+3/5

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10(dy)/(dx)+20y=12

10 \frac{d y}{d x} + 20 y = 12

y = - \frac{e ^{- 2 x - c_{1}}}{5} + \frac{3}{5}

Solution steps

10 \frac{d y}{d x} + 20 y = 12

Solve separable ODE:

y = - \frac{e ^{- 2 x - c_{1}}}{5} + \frac{3}{5}

y = - \frac{e ^{- 2 x - c_{1}}}{5} + \frac{3}{5}

\frac{d}{d x} (\frac{x ^{3}}{9})

\int_{2}^{6} \frac{x}{x - 2} d x

x^{4} + 8 x^{2} - x

f^{^{'}} (x) = x^{3} + 6 x^{2}

\frac{d y}{d x} = y^{2} x, y (0) = 6

What is the solution for 10(dy)/(dx)+20y=12 ?
The solution for 10(dy)/(dx)+20y=12 is y=-(e^{-2x-c_{1}})/5+3/5