What is the solution for (dy)/(dx)=e^{2x-5y} ?

The solution for (dy)/(dx)=e^{2x-5y} is y=(ln(5/2 e^{2x}+c_{1}))/5

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(dy)/(dx)=e^{2x-5y}

\frac{d y}{d x} = e^{2 x - 5 y}

y = \frac{ln ( \frac{5}{2} e ^{2 x} + c _{1} )}{5}

Solution steps

\frac{d y}{d x} = e^{2 x - 5 y}

Solve separable ODE:

y = \frac{ln ( \frac{5}{2} e ^{2 x} + c _{1} )}{5}

y = \frac{ln ( \frac{5}{2} e ^{2 x} + c _{1} )}{5}

y^{^{'}} = \frac{x ^{2} + 2 y ^{2}}{x y}

y^{^{''}} - y^{^{'}} - 30 = 0

569 + t (37 t^{0.6} - 108)

\frac{d r}{d θ} = \frac{r ^{2} + 10 r θ}{5 θ ^{2}}

\int 5 e^{2 x - 1} d x

What is the solution for (dy)/(dx)=e^{2x-5y} ?
The solution for (dy)/(dx)=e^{2x-5y} is y=(ln(5/2 e^{2x}+c_{1}))/5