What is the integral of (2sin(x))/1 ?

The integral of (2sin(x))/1 is -2cos(x)+C

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integral of (2sin(x))/1

\int \frac{2 sin ( x )}{1} d x

- 2 cos (x) + C

Solution steps

\int \frac{2 sin ( x )}{1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 2 (- cos (x))

Simplify

= - 2 cos (x)

Add a constant to the solution

= - 2 cos (x) + C

f (x) = (ln (x))^{4}, at x = 7

\frac{\partial}{\partial x} (3 y^{2} - x)

\int (x^{2} + 5)^{3} d x

3 - t

\int cos^{2} (π x) d x