What is the inverse of f(x)=log_{2}(log_{10}(x)) ?

The inverse of f(x)=log_{2}(log_{10}(x)) is 10^{2^x}

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inverse of f(x)=log_{2}(log_{10}(x))

inverse

f (x) = lo g_{2} (lo g_{10} (x))

1 0^{2^{x}}

Solution steps

y = lo g_{2} (lo g_{10} (x))

Replace

x

with

y

x = lo g_{2} (lo g_{10} (y))

Solve for

y, x = lo g_{2} (lo g_{10} (y))

1 0^{2^{x}}

f (x) = \frac{- 8}{x ^{2} - 4}

\frac{2 y + 6}{3 y + 2}

f (x) = f (x) = x^{2} + 2

f (x) = \frac{3 - 4 x}{5 x + 1}

\frac{2 s - 8}{s ^{2} - 4 s - 4}

What is the inverse of f(x)=log_{2}(log_{10}(x)) ?
The inverse of f(x)=log_{2}(log_{10}(x)) is 10^{2^x}