What is the inverse of f(x)=(-8)/(x^2-4) ?

The inverse of f(x)=(-8)/(x^2-4) is sqrt((-8+4x)/x),-sqrt((-8+4x)/x)

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inverse of f(x)=(-8)/(x^2-4)

inverse

f (x) = \frac{- 8}{x ^{2} - 4}

\frac{- 8 + 4 x}{x}, - \frac{- 8 + 4 x}{x}

Solution steps

y = \frac{- 8}{x ^{2} - 4}

Replace

x

with

y

x = \frac{- 8}{y ^{2} - 4}

Solve for

y, x = \frac{- 8}{y ^{2} - 4}

\frac{- 8 + 4 x}{x}, - \frac{- 8 + 4 x}{x}

\frac{2 y + 6}{3 y + 2}

f (x) = f (x) = x^{2} + 2

f (x) = \frac{3 - 4 x}{5 x + 1}

\frac{2 s - 8}{s ^{2} - 4 s - 4}

y = - 4.9 (x + 3)^{2} + 45.8

What is the inverse of f(x)=(-8)/(x^2-4) ?
The inverse of f(x)=(-8)/(x^2-4) is sqrt((-8+4x)/x),-sqrt((-8+4x)/x)