What is the inverse of f(x)=7(x-8)^2+5 ?

The inverse of f(x)=7(x-8)^2+5 is sqrt((x-5)/7)+8,-sqrt((x-5)/7)+8

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inverse of f(x)=7(x-8)^2+5

inverse

f (x) = 7 (x - 8)^{2} + 5

\frac{x - 5}{7} + 8, - \frac{x - 5}{7} + 8

Solution steps

y = 7 (x - 8)^{2} + 5

Replace

x

with

y

x = 7 (y - 8)^{2} + 5

Solve for

y, x = 7 (y - 8)^{2} + 5

\frac{x - 5}{7} + 8, - \frac{x - 5}{7} + 8

f (x) = \frac{( 3 x + 1 )}{( 11 x - 2 )}

f (x) = 1 + e^{1 + 1 - x}

7 m

f (x) = \frac{z ^{- 1}}{2 \cdot ( 1 - z ^{- 1} )}

f (x) = \frac{x ^{2} + 2}{x - 1}

What is the inverse of f(x)=7(x-8)^2+5 ?
The inverse of f(x)=7(x-8)^2+5 is sqrt((x-5)/7)+8,-sqrt((x-5)/7)+8