What is the inverse of f(x)=(x+1)^2+(y-2)^2=49 ?

The inverse of f(x)=(x+1)^2+(y-2)^2=49 is None

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inverse of f(x)=(x+1)^2+(y-2)^2=49

inverse

f (x) = (x + 1)^{2} + (y - 2)^{2} = 49

None

Solution steps

y = 49

Since the function is a constant function it has no inverse function

None

f (x) = - \frac{( x + 17 )}{3}

f (x) = (x - 4)^{2} - 8

f (x) = \frac{7 x - 9}{6 x + 5}

\frac{lo g _{5} ( 3 ^{(x)} + 9 )}{( 2 )}

\frac{( - lo g _{2} ( x ) + 5 )}{8}

What is the inverse of f(x)=(x+1)^2+(y-2)^2=49 ?
The inverse of f(x)=(x+1)^2+(y-2)^2=49 is None