What is the inverse of f(x)=5t^2-7 ?

The inverse of f(x)=5t^2-7 is sqrt((t+7)/5),-sqrt((t+7)/5)

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inverse of f(x)=5t^2-7

inverse

f (x) = 5 t^{2} - 7

\frac{t + 7}{5}, - \frac{t + 7}{5}

Solution steps

x = 5 t^{2} - 7

Replace

t

with

x

t = 5 x^{2} - 7

Solve for

x, t = 5 x^{2} - 7

\frac{t + 7}{5}, - \frac{t + 7}{5}

arcsec (x) \frac{2}{3}

\frac{- 3 x - 11}{2 x - 8}

f (x) = 2 x^{7} + 7

f (x) = - 5 (- 5 x - 9)^{2} - 6, x \geq - 95

f (x) = 1 + 2 (1 - \frac{2}{x + 1})

What is the inverse of f(x)=5t^2-7 ?
The inverse of f(x)=5t^2-7 is sqrt((t+7)/5),-sqrt((t+7)/5)