What is the domain of f(x)=(ln(x+1))/(x-sqrt(3+2x)) ?

The domain of f(x)=(ln(x+1))/(x-sqrt(3+2x)) is -1 3

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domain of f(x)=(ln(x+1))/(x-sqrt(3+2x))

domain

f (x) = \frac{ln ( x + 1 )}{x - 3 + 2 x}

- 1 < x < 3 or x > 3

Interval Notation

(- 1, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{2}

Find positive values for logs:

x > - 1

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 1 < x < 3 or x > 3

g (x) = \frac{x - 4}{3}

f (x) = x^{2} - 9 + 4 - x

f (x) = ln (x^{2} + 9)

y = \frac{x ^{2} + x - 12}{x ^{2} - 4}

What is the domain of f(x)=(ln(x+1))/(x-sqrt(3+2x)) ?
The domain of f(x)=(ln(x+1))/(x-sqrt(3+2x)) is -1<x<3\lor x>3