What is the domain of f(x)=sqrt(x^2-9)+sqrt(4-x) ?

The domain of f(x)=sqrt(x^2-9)+sqrt(4-x) is x<=-3\lor 3<= x<= 4

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domain of f(x)=sqrt(x^2-9)+sqrt(4-x)

domain

f (x) = x^{2} - 9 + 4 - x

x \leq - 3 or 3 \leq x \leq 4

Interval Notation

(- \infty, - 3] \cup [3, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 3 or 3 \leq x \leq 4

The function domain

x \leq - 3 or 3 \leq x \leq 4

f (x) = ln (x^{2} + 9)

y = \frac{x ^{2} + x - 12}{x ^{2} - 4}

h (x) = \frac{x + 5}{x ^{2} - 9}

y = 4 + \frac{5}{1 + x - 3}

What is the domain of f(x)=sqrt(x^2-9)+sqrt(4-x) ?
The domain of f(x)=sqrt(x^2-9)+sqrt(4-x) is x<=-3\lor 3<= x<= 4