What is the domain of y=(3ln^2(x))/x ?

The domain of y=(3ln^2(x))/x is x>0

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domain of y=(3ln^2(x))/x

domain

y = \frac{3 ln ^{2} ( x )}{x}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find positive values for logs:

x > 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = (x - 2) (x^{2} + 3 x)

f (x) = \frac{4 x - 2 x ^{2}}{x - 2}

f (x) = lo g_{10} (\frac{x ^{2} - 9}{x - 3})

\frac{1}{3} x - 3

g (x) = \frac{x + 8}{x ^{2} - 16 + 64}